x^2+36x=252

Solution for x^2+36x=252 equation:

x^2+36x=252

We move all terms to the left:

x^2+36x-(252)=0

a = 1; b = 36; c = -252;
Δ = b2-4ac
Δ = 362-4·1·(-252)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-48}{2*1}=\frac{-84}{2}
=-42
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+48}{2*1}=\frac{12}{2}
=6
$